Focal chord of y 2 16x is a tangent
WebJan 23, 2024 · Here, the focal chord to y2 =16x is tangent to circle (x−6)2+y2 =2 ⇒ focus of the parabola is (4,0) Now, tangent are drawn from (4,0) to (x−6)2+y2=2 Since, P A is tangent to circle and equals to 2 , (from diagram using distance formula) tanθ= slope of tangent =AP AC = 2 2 =1 or tanθ =BP BC =−1 ∴ Slope of focal chord as tangent to … WebDec 23, 2024 · The tangent to the Parabola that is parallel to y=4x+1 is: y = 4x+5/16 Which meets the Parabola at the coordinate: (5/64,5/8) We have a parabola given by: y^2=5x graph{y^2=5x [-5, 5, -5, 5]} The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. So if we differentiate the parabola …
Focal chord of y 2 16x is a tangent
Did you know?
WebStep-1 Length of tangent : Given: The focal chord to y 2 = 16 x is tangent to (x – 6) 2 + y 2 = 2. The standard equation of the parabola is: y 2 = 4 a x. Comparing the given … WebA: Here, Circle with center O is having tangents JK, KL and JL. so JA¯≅JB¯ ⇒JA=JB (tangent to circle… question_answer Q: Find the surface area of the cone in terms of it.
WebThe equation of a common tangent to the curves, y 2=16x and xy=−4 is A x+y+4=0 B x−2y+16=0 C 2x−y+2=0 D x−y+4=0 Medium Solution Verified by Toppr Correct option is D) Step 1: Use slope form of tangent equation of parabola Equation of tangent to parabola y 2=4ax in terms of slope ’m’ is y=mx+ ma WebMay 6, 2016 · Question: Prove that the directrix is tangent to the circles that are drawn on a focal chord of a parabola as diameter. ... Prove that in a parabola the tangent at one end of a focal chord is parallel to the normal at the other end. 0.
WebThe focal chord of the parabola (y−2) 2=16(x−1) is a tangent to the circle x 2+y 2−14x−4y+51=0, then the focal chord can be A 0 B 1 C 2 D 3 Medium Solution Verified by Toppr Correct option is B) Was this answer helpful? 0 0 Similar questions If points (au 2,2au) and (av 2,2av) are extremities of the focal chord of a parabola y 2=4ax, then Hard WebMar 14, 2024 · Consider a parabola y 2 = 4 a x , parameterize it as x = a t 2 and y = 2 a t, then it is found that if we have a line segment passing through focus, with each points having value of t as t 1 and t 2 for the parameterization, then it must be that: t 1 ⋅ t 2 = − 1 Hope for hints. conic-sections Share Cite Follow edited Mar 14, 2024 at 15:05
WebHere, the focal chord of y 2 = 16 x is tangent to circle (x − 6) 2 + y 2 = 2 ⇒ Focus of parabola as (a, 0) i.e. (4, 0) Now, tangents are drawn from (4, 0) to (x − 6) 2 + y 2 = 2. Since, P A is tangent to circle. ∴ t a n θ = slope of tangent = A C A P = √ 2 √ 2 = 1, or B C B P = − 1. ∴ Slope of focal chord as tangent to circle ...
WebJan 11, 2024 · The focal chord to `y^2=16x` is tangent to `(x-6)^2+ y^2 =2` then the possible values of the slope of this chord asked Nov 15, 2024 in Parabola by kundansingh ( 95.2k points) class-12 mcnamee lochner albanyWebMay 20, 2024 · The equation of common tangent to the curves y^2 = 16x and xy = –4, is : ... If one end of a focal chord of the parabola, y^2 = 16x is at (1, 4), then the length of this focal chord is : asked May 18, 2024 in Mathematics by Jagan (21.2k points) jee mains 2024; 0 votes. 1 answer. mcnamee lochner titus \u0026 williamsWeb2) are the endpoints of a focal chord then t 1 t 2 = −1. (2) Tangents at endpoints of a focal chord are perpendicular and hence intersect on directrix. (3) Length of a focal chord of y2 = 4ax, making an angle αwith the X-axis, is 4acosec2α. (4) If AB is a focal chord of y2 = 4ax, then , where S is the focus. Recall mcnamee lochner titus \\u0026 williams p.cWebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are mcnamee lochner titusWebMath Advanced Math If a focal chord of y =16x is a tangent to the circle (x-6)° +y² = 2, then the positive value of the slope of this chord is. If a focal chord of y =16x is a … lifecare greenbush mnWebGet an expert solution to The focal chord of the parabola ( y − 2 ) 2 = 16 ( x − 1 ) is a tangent to the circle x 2 + y 2 − 14 x − 4 y + 51 = 0 , then slope of the focal chord can be lifecare health labWebOct 14, 2024 · The focal chord to y^2 =16x is tangent to (x–6)^2 +y2 = 2, then the possible value of the slope of this chord, are asked Oct 22, 2024 in Parabola by deepikaben ( … lifecare greenbush manor mn